Smooch backdrop
Smooch poster

Stream On

Data provided by JustWatch. Availability may vary by region.

Smooch

"A modern twist on a timeless tale."

6.0/ 10 · 0K votes
2011-02-05
1h 28m
EN
Released

Storyline

An imaginative youngster comes across an amnesiac prince, who she believes is a fairy-tale figure. Convinced the man would be perfect for her widowed mom, she launches a plan to set the two up, starting by tricking her mom into hiring him as the new nanny.

0

Production

Beantown Ranch Entertainment
SilverScreen PicturesSilverScreen Pictures
Sponsored

Cast

Advertisement

Videos & Trailers

Reviews

Loading reviews...

Frequently Asked Questions

Where can I watch Smooch?+

Smooch is available to stream on fuboTV, Philo, YouTube TV, Hallmark+ Amazon Channel, Hallmark+ Apple TV Channel, Hallmark TV Amazon Channel. Availability may vary by region.

When was Smooch released?+

Smooch was released on February 5, 2011.

Who directed Smooch?+

Smooch was directed by Ron Oliver.

Who stars in Smooch?+

The main cast of Smooch includes Kellie Martin, Kiernan Shipka, Nick Ullett, Rod Myers.

How long is Smooch?+

Smooch has a runtime of 1h 28m.

What genre is Smooch?+

Smooch is classified as Romance, TV Movie.

What is the rating of Smooch?+

Smooch has an average audience rating of 6.0 out of 10, based on 50 votes.

How to watch Smooch online?+

You can watch Smooch (2011) online by streaming it on fuboTV, Philo, YouTube TV, Hallmark+ Amazon Channel, Hallmark+ Apple TV Channel, Hallmark TV Amazon Channel. Streaming availability may vary depending on your region and subscription.

Is Smooch available on any streaming platform?+

Yes, Smooch is currently available to stream on fuboTV, Philo, YouTube TV, Hallmark+ Amazon Channel, Hallmark+ Apple TV Channel, Hallmark TV Amazon Channel. Check the platform for the latest availability in your country.

What is the OTT release date of Smooch?+

Smooch had its theatrical/initial release on February 5, 2011. Its OTT (streaming) release date will be listed here once a platform confirms it.